1. If a metallic cone of radius 30 cm and height 45 cm is melted and recast into metallic spheres of radius 5 cm, find the number of spheres.
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- By: anil on 05 May 2019 01.56 amVolume of metallic cone = $$frac{1}{3} pi r^2 h$$ = $$frac{1}{3} pi * 30^2 * 45 = 13500 pi cm^3$$ Volume of sphere = $$frac{4}{3} pi R^3$$ = $$frac{4}{3} pi * 5^3 = frac{500 pi}{3} cm^3$$ => Required no. of spheres = $$frac{13500 pi}{frac{500 pi}{3}}$$ = 81
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