1. Three circles of radius a, b, c touch each other externally. The area of the triangle formed by joining their centres is
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By: anil on 05 May 2019 01.56 am
Let sides of triangle be x,y,z => x = AB = a+b y = BC = b+c z = CA = a+c Thus, semi perimeter(s) = $$frac{AB + BC + CA}{2} = a+b+c$$ Area of $$ riangle$$ABC = $$sqrt{s(s-a)(s-b)(s-c)}$$ = $$sqrt{(a+b+c)abc}$$
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