1. A spherical ball of lead of radius 14 cm is melted and recast into spheres of radius 2 cm. The number of the small spheres is
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By: anil on 05 May 2019 02.24 am
Radius of large spherical ball = $$R=14$$ cm and radius of small spheres = $$r=2$$ cm => Number of balls = Volume of large ball/Volume of small sphere = $$frac{frac{4}{3}pi R^3}{frac{4}{3}pi r^3}$$ = $$frac{(14)^3}{(2)^3}=(frac{14}{2})^3$$ = $$(7)^3=343$$ => Ans - (C)
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