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Multiple Choice Questions
1. I. $$6x^{2}+29x+35=0$$II. $$3y^{2} +11y+10=0$$
(A): x > y
(B): x ≥ y
(C): x < y
(D): x ≤ y
(E): x = y or the relation cannot be established.
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By: anil on 05 May 2019 01.38 am
I.$$6x^{2} + 29x + 35 = 0$$ => $$6x^2 + 15x + 14x + 35 = 0$$ => $$3x (2x + 5) + 7 (2x + 5) = 0$$ => $$(2x + 5) (3x + 7) = 0$$ => $$x = frac{-7}{3} , frac{-5}{2}$$ II.$$3y^{2} + 11y + 10 = 0$$ => $$3y^2 + 6y + 5y + 10 = 0$$ => $$3y (y + 2) + 5 (y + 2) = 0$$ => $$(y + 2) (3y + 5) = 0$$ => $$y = -2 , frac{-5}{3}$$ Hence $$x < y$$
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IBPS RRB Clerk 6 Sep 2014
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