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Multiple Choice Questions
1. I. $$2x^{2}+18x+40=0$$ II. $$2y^{2} +15y+27=0$$
(A): x > y
(B): x ≥ y
(C): x < y
(D): x ≤ y
(E): x = y or the relation cannot be established.
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By: anil on 05 May 2019 01.38 am
I.$$2x^{2} + 18x + 40 = 0$$ => $$2x^2 + 8x + 10x + 40 = 0$$ => $$2x (x + 4) + 10 (x + 4) = 0$$ => $$(x + 4) (2x + 10) = 0$$ => $$x = -4 , -5$$ II.$$2y^{2} + 15y + 27 = 0$$ => $$2y^2 + 6y + 9y + 27 = 0$$ => $$2y (y + 3) + 9 (y + 3) = 0$$ => $$(y + 3) (2y + 9) = 0$$ => $$y = -3 , frac{-9}{2}$$ $$ herefore$$ No relation can be established.
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IBPS RRB Clerk 6 Sep 2014
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