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Multiple Choice Questions
1. I. $$ 2x^{2}+15x+28=0 $$ II. $$4y^{2} +18y+14=0 $$
(A): x > y
(B): x ≥ y
(C): x < y
(D): x ≤ y
(E): x = y or the relation cannot be established.
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By: anil on 05 May 2019 01.38 am
I.$$2x^{2} + 15x + 28 = 0$$ => $$2x^2 + 8x + 7x + 28 = 0$$ => $$2x (x + 4) + 7 (x + 4) = 0$$ => $$(x + 4) (2x + 7) = 0$$ => $$x = -4 , frac{-7}{2}$$ II.$$4y^{2} + 18y + 14 = 0$$ => $$4y^2 + 4y + 14y + 14 = 0$$ => $$4y (y + 1) + 14 (y +1) = 0$$ => $$(y + 1) (4y + 14) = 0$$ => $$y = -1 , frac{-7}{2}$$ $$ herefore x leq y$$
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IBPS RRB Clerk 6 Sep 2014
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