1. A tennis ball is initially dropped from a height of 180 m. After striking the ground, it rebounds (3/5)th of the height from which it has fallen. The total distance that the ball travels before it comes to rest is
Write Comment
Comments
By: anil on 05 May 2019 02.39 am
While going down the ball will first cover $$180$$m, then $$frac{180*3}{5}$$, then $$frac{180*3*3}{5*5}$$ and so on.
After rebouncing the ball will cover $$frac{180*3}{5}$$, then $$frac{180*3*3}{5*5}$$ and so on
Thus, there are 2 infinite G.Ps here one of $$180$$, $$frac{180*3}{5}$$, $$frac{180*3*3}{5*5}$$,......
and other $$frac{180*3}{5}$$, $$frac{180*3*3}{5*5}$$,.........
Total distance covered by the ball = Distance covered while going up + Distance covered while going down
= $$frac{180}{1-frac{3}{5}} + frac{180*frac{3}{5}}{1-frac{3}{5}}$$ = $$720$$ m.
Hence, option C is the correct answer.
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use
After rebouncing the ball will cover $$frac{180*3}{5}$$, then $$frac{180*3*3}{5*5}$$ and so on
Thus, there are 2 infinite G.Ps here one of $$180$$, $$frac{180*3}{5}$$, $$frac{180*3*3}{5*5}$$,......
and other $$frac{180*3}{5}$$, $$frac{180*3*3}{5*5}$$,.........
Total distance covered by the ball = Distance covered while going up + Distance covered while going down
= $$frac{180}{1-frac{3}{5}} + frac{180*frac{3}{5}}{1-frac{3}{5}}$$ = $$720$$ m.
Hence, option C is the correct answer.