1. Last year, 5 companies had an average of 16 non working days each. This year 3 companies had 10 more non working days each, and 2 companies had 5 fewer non working days each. What was the average number of non working days given by the same companies this year ?
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By: anil on 05 May 2019 02.27 am
Total number of non working days by 5 companies last year = $$5 imes16=80$$ Non working days this year = $$80+(3 imes10)-(2 imes5)=100$$ => Required average = $$frac{100}{5}=20$$ => Ans - (C)
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