1. The lengths of two diagonals of a rhombus are 24 cm and 32 cm. What is the side (in cm) of the rhombus?
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By: anil on 05 May 2019 02.24 am
Give : ABCD is a rhombus, AC = 24 cm and BD = 32 cm To find : AB = ? Solution : Diagonals of a rhombus bisect each other at right angle. => OA = $$frac{24}{2}=12$$ cm and OB = $$frac{32}{2}=16$$ cm Thus, in $$ riangle$$ OAB, => $$(AB)^2=(OA)^2+(OB)^2$$ => $$(AB)^2=(12)^2+(16)^2$$
=> $$(AB)^2=144+256=400$$ => $$AB=sqrt{400}=20$$ cm => Ans - (A)
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=> $$(AB)^2=144+256=400$$ => $$AB=sqrt{400}=20$$ cm => Ans - (A)