1. The lengths of diagonals of a rhombus are 24cm and 10cm the perimeter of the rhombus (in cm ) is :
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By: anil on 05 May 2019 01.48 am
The diagonals of a rhombus bisect each other at right angle. ABCD is the rhombus whose diagonals bisect at O. Given : BD = 24 cm and AC = 10 cm => $$OB=frac{BD}{2}=12$$ cm Similarly, $$OA=5$$ cm In $$ riangle$$ OAB => $$(AB)^2=(OA)^2+(OB)^2$$ => $$(AB)^2 = (5)^2+(12)^2$$ => $$(AB)^2=25+144=169$$ => $$AB=sqrt{169}=13$$ cm $$ herefore$$ Perimeter of rhombus = $$4 imes AB$$ [$$ecause$$ All sides of rhombus are equal] = $$4 imes 13=52$$ cm => Ans - (A)
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