1. A wooden bowl is in shape of a hollow hemisphere of internal radius 7 cm and thickness 1 cm. What is the total surface area (in sq.cm) of the bowl? (Take: π = 22/7)
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By: anil on 05 May 2019 02.17 am
The hemispherical bowl has three surfaces to calculate : the interior hemisphere $$(r_{int} = 7)$$ cm , the exterior hemisphere $$(r_{ext} = 7+1 = 8)$$ cm and the annular(ring shaped) top edge $$(r_{ext} , r_{int})$$ Area of hemisphere = $$2 pi r^2$$ and area of annular = $$pi (r^2_{ext} - r^2{int})$$ Total surface area of hemisphere is the sum of these 3 areas = $$[2 pi (7)^2] + [2 pi (8)^2] + [pi (8^2 - 7^2)]$$ = $$pi (98 + 128 + 64 - 49) = 241 pi$$ = $$241 imes frac{22}{7} = 757.43 cm^2$$
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