1. A square is inscribed in a circle. If the side of the square is 14 cm, what is the area (in sq.cm) of the circle?
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By: anil on 05 May 2019 02.17 am
Square is inscribed in circle, thus diagonal of square = diameter of circle
Side of square = BC = CD = 14 cm
In $$ riangle$$ BCD => $$BD = sqrt{(BC)^2 + (CD)^2}$$ => $$BD = sqrt{(14)^2 + (14)^2} = sqrt{196 + 196}$$ => $$BD = sqrt{392} = 14sqrt{2}$$ => Radius of circle $$r = 7sqrt{2}$$ cm $$ herefore$$ Area of circle = $$pi r^2$$ = $$pi (7sqrt{2})^2 = 98 pi cm^2$$
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Side of square = BC = CD = 14 cm
In $$ riangle$$ BCD => $$BD = sqrt{(BC)^2 + (CD)^2}$$ => $$BD = sqrt{(14)^2 + (14)^2} = sqrt{196 + 196}$$ => $$BD = sqrt{392} = 14sqrt{2}$$ => Radius of circle $$r = 7sqrt{2}$$ cm $$ herefore$$ Area of circle = $$pi r^2$$ = $$pi (7sqrt{2})^2 = 98 pi cm^2$$