1. What least number must be added to 1039, so that the sum obtained is completely divisible by 29?
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By: anil on 05 May 2019 02.17 am
Factorizing 1039 = 29 $$ imes$$ 35 + 24 Thus, on dividing 1039 by 29, the remainder is 24 $$ herefore$$ The number that must be added to 1039 so that the sum obtained is completely divisible by 29 = 29 - 24 = 5 => Ans - (B)
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