1. Two students appeared for an examination. One of them secured 13 marks more than the other and his marks were 76% of the sum of their marks. The marks obtained by them are
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By: anil on 05 May 2019 02.17 am
Let marks scored by 1st student = $$x$$
=> Marks scored by another student = $$(x + 13)$$ According to question, => $$(x + 13) = frac{76}{100} imes (x + x + 13)$$ => $$x + 13 = frac{19}{25} imes (2x + 13)$$ => $$25x + 325 = 38x + 247$$ => $$38x - 25x = 325 - 247 = 78$$ => $$x = frac{78}{13} = 6$$ $$ herefore$$ Marks scored by other student = 6 + 13 = 19
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=> Marks scored by another student = $$(x + 13)$$ According to question, => $$(x + 13) = frac{76}{100} imes (x + x + 13)$$ => $$x + 13 = frac{19}{25} imes (2x + 13)$$ => $$25x + 325 = 38x + 247$$ => $$38x - 25x = 325 - 247 = 78$$ => $$x = frac{78}{13} = 6$$ $$ herefore$$ Marks scored by other student = 6 + 13 = 19