1. If Anuj walks at the speed of 4 km/hr, then he reaches his school 6 minutes late but if he walks at the speed of 5 km/hr, then he reaches 6 minutes before the scheduled time. What is the distance (in km) of his school from his house?
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By: anil on 05 May 2019 02.06 am
Let distance between school and house = $$d$$ km and ideal time to reach school = $$t$$ hours When he walks at a speed of 4 km/hr, he reaches school 6 minutes late, => using distance = speed $$ imes$$ time => $$d=4 imes(t+frac{6}{60})$$ ---------------(i) Similarly, $$d=5 imes(t-frac{6}{60})$$ --------------(ii) Comparing, equations (i) and (ii), we get : => $$4(t+frac{6}{60})=5(t-frac{6}{60})$$ => $$4t+frac{2}{5}=5t-frac{1}{2}$$ => $$5t-4t=frac{2}{5}+frac{1}{2}$$ => $$t=frac{(4+5)}{10}=frac{9}{10}$$ Substituting it in equation (i), => $$d=4(frac{9}{10}+frac{6}{60})$$ = $$4(frac{(54+6)}{60})=frac{60}{15}=4$$ km => Ans - (A)
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