1. AB is the chord of circle of length 6 cm. From the center of the circle a perpendicular is drawn which intersects the chord at M and distance between centre and chord is 4 cm. find the area $$(in cm^2)$$ of the circle)





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  • By: anil on 05 May 2019 02.04 am
    Given : AB = 6 cm and OM = 4 cm To find : Area of circle = ? Solution : Let $$r$$ be the radius of circle Also, MB = $$frac{6}{2}=3$$ cm In right $$ riangle$$ MOB, => $$(OB)^2=(OM)^2+(MB)^2$$ => $$(OB)^2=(4)^2+(3)^2$$
    => $$r^2=16+9=25$$ => $$r=sqrt{25}=5$$ cm $$ herefore$$ Area of circle = $$pi r^2$$
    = $$3.14 imes(5)^2=78.5$$ $$cm^2$$ => Ans - (D)
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