1. The two chords AB and CD of a circle intersect at point P, such that BP=4 cm, PD=5 cm, and CP=8 cm. find the length of chord AB.
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By: anil on 05 May 2019 02.04 am
Given : AB and CD are chords of the circle which intersect at point P. BP = 4 cm, CP = 8 cm and PD = 5 cm To find : AB = ? Solution : Let AP = $$x$$ cm Now, when two chords intersect each other inside a circle, the products of their segments are equal. => $$(AP) imes(BP)=(CP) imes(DP)$$ => $$x imes4=8 imes5$$ => $$x=frac{40}{4}=10$$ $$ herefore$$ AB = AP + PB = $$10+4=14$$ cm => Ans - (D)
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