1. The heights of two similar right-angled triangles ΔLMN and ΔOPQ are 48 cm and 36 cm. If OP = 12 cm, then LM is
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By: anil on 05 May 2019 01.53 am
ratio of heights of two similar triangles is always equal to the ratio of the corresponding sides of the triangles i.e, $$frac{ ext{height of } riangle LMN}{ ext{height of } riangle OPQ}$$ = $$frac{ ext{length of LM}}{ ext{length of OP}}$$
put in values from the question
$$frac{48}{36}$$ = $$frac{ ext{length of LM}}{12}$$
length of LM = 16
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put in values from the question
$$frac{48}{36}$$ = $$frac{ ext{length of LM}}{12}$$
length of LM = 16