1. The radius of a circle is 6 cm. An external point is at a distance of 10 cm from the centre. Then the length of the tangent drawn to the circle from the external point upto the point of contact is





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  • By: anil on 05 May 2019 01.51 am
    Given : OA = 6 cm and OB = 10 cm To find : AB = ? Solution : From $$ riangle$$OAB
    => $$AB = sqrt{(OB)^2 - (OA)^2}$$ = $$sqrt{10^2 - 6^2} = sqrt{64}$$ = 8 cm
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