1. O is an centre of a circle. P is an external point of it at distance of 13cm from O. The radius of the circle is 5cm. Then the length of a tangent to the circle from P upto the point of contact is
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By: anil on 05 May 2019 01.48 am
Given : OT is radius of circle = 5 cm and OP = 13 cm To find : Tangent PT = ? Solution : The radius of a circle intersects the tangent at right angle, => $$angle OTP = 90^circ$$ Thus in $$ riangle$$ OPT, => $$(PT)^2=(OP)^2-(OT)^2$$ => $$(PT)^2=(13)^2-(5)^2$$ => $$(PT)^2=169-25=144$$ => $$PT=sqrt{144}=12$$ cm => Ans - (C)
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