Given : AB = 16 cm and OB = 10 cm To find : OC = ? Solution : The line from the centre of the circle to the chord bisects it at right angle. => AC = BC = $$frac{1}{2}$$ AB => BC = $$frac{16}{2}=8$$ cm In $$ riangle$$ OBC, => $$(OC)^2=(OB)^2-(BC)^2$$ => $$(OC)^2=(10)^2-(8)^2$$ => $$(OC)^2=100-64=36$$ => $$OC=sqrt{36}=6$$ cm => Ans - (B)