1. The length of a chord which is at a distance of 12 cm from the centre of a circle of radius 13 cm is
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By: anil on 05 May 2019 01.48 am
Given : OB is the radius of circle = 13 cm and OC = 12 cm To find : AB = ? Solution : The line from the centre of the circle to the chord bisects it at right angle. => AC = BC = $$frac{1}{2}$$ AB In $$ riangle$$ OBC,
=> $$(BC)^2=(OB)^2-(OC)^2$$ => $$(BC)^2=(13)^2-(12)^2$$ => $$(BC)^2=169-144=25$$ => $$BC=sqrt{25}=5$$ cm $$ herefore$$ AB = $$2 imes$$ BC = $$2 imes 5=10$$ cm => Ans - (A)
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=> $$(BC)^2=(OB)^2-(OC)^2$$ => $$(BC)^2=(13)^2-(12)^2$$ => $$(BC)^2=169-144=25$$ => $$BC=sqrt{25}=5$$ cm $$ herefore$$ AB = $$2 imes$$ BC = $$2 imes 5=10$$ cm => Ans - (A)