1. Two trains are moving in the opposite directions at speed of 43 km/h and 51 km/h respectively. The time taken by the slower train to cross a man sitting in the faster train is 9 seconds. What is the length (in metres) of the slower train?
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By: anil on 05 May 2019 01.47 am
Speed of the two trains = 43 km/h and 51 km/h Since the trains are moving in opposite directions, => Relative speed = 43 + 51 = 94 km/h = $$(94 imesfrac{5}{18})$$ m/s = $$(frac{235}{9})$$ m/s Since the observation given is of a passenger sitting in faster train, distance travelled is equal to length of the slower train. Let it be = $$d$$ m
Using, distance = speed x time => $$d=frac{235}{9} imes9=235$$ m => Ans - (A)
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Using, distance = speed x time => $$d=frac{235}{9} imes9=235$$ m => Ans - (A)