1. A chord of length 60 cm is at a distance of 16 cm from the centre of a circle. What is the radius (in cm) of the circle?
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By: anil on 05 May 2019 01.47 am
Given : AB = 60 cm and OC = 16 cm To find : OB = $$r$$ = ? Solution : The line from the centre of the circle to the chord bisects it at right angle. => AC = BC = $$frac{1}{2}$$ AB => BC = $$frac{60}{2}=30$$ cm In $$ riangle$$ OBC, => $$(OB)^2=(BC)^2+(OC)^2$$ => $$(OB)^2=(30)^2+(16)^2$$ => $$(OB)^2=900+256=1156$$ => $$OB=sqrt{1156}=34$$ cm => Ans - (B)
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