1. The internal bisectors of ∠Q and ∠R of triangle PQR meet at O. If ∠P = 70°, then what is the measure of ∠QOR (in degrees)?
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By: anil on 05 May 2019 01.47 am
Given : O is the incentre of $$ riangle$$ PQR and $$angle$$ P = 70° To find : $$angle$$ QOR = $$ heta$$ = ? Incentre of a triangle = $$90^circ+frac{1}{2} imes $$ (Angle opposite to it) => $$ heta=90^circ+frac{70^circ}{2}$$ => $$ heta=90^circ+35^circ$$ => $$ heta=125^circ$$ => Ans - (C)
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