1. In triangle PQR, the sides PQ and PR are produced to A and B respectively. The bisectors of ∠AQR and ∠BRQ intersect at point O. If ∠QOR = 50°, then what is the value (in degrees) of ∠QPR?
Write Comment
Comments
By: anil on 05 May 2019 01.47 am
Given : O is the excentre of $$ riangle$$ PQR and ∠QOR = 50° To find : $$angle$$ QPR = $$ heta$$ = ? Excentre of a triangle = $$90^circ-frac{1}{2} imes $$ (Angle opposite to it) => $$50^circ=90^circ-frac{ heta}{2}$$ => $$frac{ heta}{2}=90-50=40^circ$$ => $$ heta=2 imes40=80^circ$$ => Ans - (C)
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use