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Study the given information carefully and answer the questions that follow:
An urn contains 3 red, 6 blue, 2 green and 4 yellow marbles.If two marbles are picked at random, what is the probability that either both are red or both are green ?
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By: anil on 05 May 2019 01.39 am
Total number of marbles in the urn = 15 P(S) = Total possible outcomes = Selecting 2 marbles at random out of 15 => $$P(S) = C^{15}_2 = frac{15 imes 14}{1 imes 2}$$ = $$105$$ P(E) = Favorable outcomes = Selecting 2 green or 2 red marbles. => $$P(E) = C^2_2 + C^3_2$$ = $$1 + frac{3 imes 2}{1 imes 2}$$ = $$4$$ $$ herefore$$ Required probability = $$frac{P(E)}{P(S)}$$ = $$frac{4}{105}$$
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