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Study the given information carefully and answer the questions that follow:
An urn contains 6 red, 4 blue, 2 green, 3 yellow marbles.If four marbles are picked at random what is the probability that one is green two are blue and one is red ?
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By: anil on 05 May 2019 01.34 am
One green marble can be selected in $$^2C_1$$ = 2 ways. Two blue marbles can be selected in $$^4C_2 = 6$$ ways Six red marbles can be selected in $$^6C_1 = 6$$ ways. Probability = $$frac{2*6*6}{^{15}C_4}$$ = 24/455
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