1.
In each of these questions two equations numbered I & II are given. You have to solve both the equations and give answer.I. $$6a^{2}-25a+25=0$$
II. $$15b^{2}-16b+4=0$$
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By: anil on 05 May 2019 01.32 am
$$6a^{2}-25a+25=0$$ => $$6a^{2}-10a-15a+25=0$$ => 2a (3a -5) -5 (3a -5) = 0 So, a = 5/2 or 5/3 $$15b^{2}-16b+4=0$$ => $$15b^{2}-10b -6b+4=0$$ => 5b (3b-2) - 2(3b - 2) = 0 So, b = 2/5 or 2/3 So, a > b
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