1.
In each of these questions two equations numbered I & II are given. You have to solve both the equations and give answer.I. $$4a^{2}-20a+21=0$$
II. $$2b^{2}-5b+3=0$$
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$$(2a-3)(2a-7) = 0$$
$$a = frac{3}{2}, frac{7}{2}$$ $$2b^2-5b+3 = 0$$
$$(2b-3)(b-1) = 0$$
$$b = 1, frac{3}{2}$$ $$ herefore ageq b$$