1. In an examination it is required to get 380 of the aggregate marks to pass. A student gets 32% of marks and is declared failed by 76 marks. What are the maximum aggregate marks a student can get ?
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By: anil on 05 May 2019 01.27 am
Let the max marks in the exam = $$100x$$ Passing marks = 380 Now, acc to ques, => $$(frac{32}{100} * 100x) + 76 = 380$$
=> $$32x = 380 - 76$$ => $$x = frac{304}{32} = 9.5$$ $$ herefore$$ Max marks = 100 * 9.5 = 950
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=> $$32x = 380 - 76$$ => $$x = frac{304}{32} = 9.5$$ $$ herefore$$ Max marks = 100 * 9.5 = 950