1. Two pieces of can full a tank in 10h and 16 h respectively. A third pipe can empty the tank in 32 h. If all the three pipes function simultaneously, then in how much time the tank will be full?? (in h)
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By: anil on 05 May 2019 01.15 am
If all the pipes are working together, then part of the tank filled in one hr will be = $$frac{1}{10} + frac{1}{16} - frac{1}{32} = frac{21}{160}$$ Hence, it will take $$frac{160}{21}$$ hr to fill the complete tank So answer will be B
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