1. A tank is fitted with two inlet pipes A and B and an outlet pipe C. Pipe A can fill the empty tank in 12 minutes. While pipe B alone can fill it in 18 minutes. Pipe C can empty the full tank in 11 1/4 minutes. If all three pipes are opened simultaneously, in what time will the empty tank be filled?
Write Comment
Comments
- By: anil on 05 May 2019 01.22 amPart of the tank filled in 1 minute when all three pipes are opened = $$frac{1}{12} + frac{1}{18} - frac{frac{1}{45}}{4}$$ = $$frac{1}{12} + frac{1}{18} - frac{4}{45}$$ = $$frac{9}{180} = frac{1}{20}$$ => Required time = 20 minutes
Show Similar Question And Answers
