1. The liquids, X and Y are mixed in the ratio of 3: 2 and the mixture is sold at ₹11 per litre at a profit of 10%. If the liquid X costs ₹2 more per litre then Y, the cost of X per litre is (in ₹):





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  • By: anil on 05 May 2019 02.19 am
    Selling price of mixture = Rs. 11 at 10% profit => Cost price of 1 litre of mixture = $$frac{11}{100+10} imes100=Rs.$$ $$10$$ Let cost of liquid X = Rs. $$x$$, => Cost of liquid Y = Rs. $$(x-2)$$ The liquids are mixed in the ratio of 3 : 2. In 5 liters of the mixture, 3 liters will be first liquid and 2 liters will be the second liquid. Thus, cost of 5 litres of mixture = $$3x+2(x-2)=5 imes10$$ => $$3x+2x-4=50$$ => $$5x=50+4=54$$ => $$x=frac{54}{5}=Rs.$$ $$10.80$$ => Ans - (B)
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