Let line $$l$$ perpendicularly bisects line joining  A(5,-3) and B(0,2) at C, thus C is the mid point of AB. => Coordinates of C = $$(frac{5 + 0}{2} , frac{-3 + 2}{2})$$ = $$(frac{5}{2} , frac{-1}{2})$$ Now, slope of AB = $$frac{y_2 - y_1}{x_2 - x_1} = frac{(2 + 3)}{(0 - 5)}$$ = $$frac{5}{-5} = -1$$ Let slope of line $$l = m$$ Product of slopes of two perpendicular lines = -1 => $$m imes -1 = -1$$ => $$m = 1$$ Equation of a line passing through point $$(x_1,y_1)$$ and having slope $$m$$ is $$(y - y_1) = m(x - x_1)$$ $$ herefore$$ Equation of line $$l$$ => $$(y + frac{1}{2}) = 1(x - frac{5}{2})$$ => $$x - y = frac{5}{2} + frac{1}{2} = frac{6}{2}$$ => $$x - y = 3$$ => Ans - (D)