Divide 20 into two parts such that the sum of the square of the parts is 232. What is the value of the two parts? ?->(Show Answer!)

1. Divide 20 into two parts such that the sum of the square of the parts is 232. What is the value of the two parts?

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By: anil on 05 May 2019 02.17 am

Let the first part = $$x$$ and second part = $$(20 - x)$$ According to ques, => $$(x)^2 + (20 - x)^2 = 232$$ => $$x^2 + (x^2 + 400 - 40x) = 232$$ => $$2x^2 - 40x + 400 - 232 = 0$$ => $$x^2 - 20x + 84 = 0$$ => $$x^2 - 6x - 14x + 84 = 0$$ => $$x(x-6) - 14(x-6) = 0$$ => $$(x-6)(x-14) = 0$$ => $$x = 6,14$$ => Ans - (A)

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