1. In an alloy, aluminium and tin are in the ratio of 4 : 5. In the second alloy, the ratio of same elements is 4 : 7. If equal quantities of these two alloys be mixed to form a new alloy, then what will be the ratio of both of these elements in the new alloy?
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By: anil on 05 May 2019 02.07 am
Ratio of aluminium and tin in first alloy = 4 : 5 Ratio of aluminium and tin in second alloy = 4 : 7 Let quantity of both alloys taken = L.C.M. (9,11) = 99 units => Aluminium in first alloy = $$frac{4}{(4+5)} imes99=44$$ units Tin present in first alloy = $$99-44=55$$ units Similarly, aluminium in second alloy = $$36$$ units and tin = $$63$$ units $$ herefore$$ Ratio of aluminium and tin in the new alloy = $$frac{(44+36)}{(55+63)}$$ = $$frac{80}{118}=frac{40}{59}$$ => Ans - (D)
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