1. In an alloy, lead and tin are in the ratio of 2 : 3. In the second alloy, the ratio of same elements is 3 : 4. If equal quantities of these two alloy are mixed to form a new alloy, then what will be the ratio of these two elements in the new alloy?
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By: anil on 05 May 2019 02.04 am
Ratio of lead and tin in first alloy = 2 : 3 Ratio of lead and tin in second alloy = 3 : 4 Let quantity of both alloys taken = L.C.M. (5,7) = 35 units => Lead in first alloy = $$frac{2}{(2+3)} imes35=14$$ units Tin present in first alloy = $$35-14=21$$ units Similarly, lead in second alloy = $$15$$ units and tin = $$20$$ units $$ herefore$$ Ratio of lead and tin in the new alloy = $$frac{(14+15)}{(21+20)}$$ = $$frac{29}{41}$$ => Ans - (B)
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