1. If a regular polygon has 10 sides then the measure of its interior angle is greater than the measure of its exterior angle by how many degrees?
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By: anil on 05 May 2019 02.06 am
Sum of all interior angles of $$n$$ sided polygon = $$(n-2) imes180^circ$$ Sum of all exterior angles = $$360^circ$$ Thus, difference between measure of an interior and exterior angle, when $$n=10$$ = $$[frac{(10-2) imes180^circ}{10}]-[frac{360^circ}{10}]$$ = $$(8 imes18^circ)-(36^circ)$$ = $$144^circ-36^circ=108^circ$$ => Ans - (D)
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