1. If the measure of the interior angle of a regular polygon is $$108^\circ$$ greater than the measure of its exterior angle then how many sides does it have?





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  • By: anil on 05 May 2019 03.01 pm
    Let the number of sides of the polygon = $$n$$ Sum of all interior angles = $$(n-2) imes180^circ$$ Sum of all exterior angles = $$360^circ$$ According to ques, => $$frac{(n-2) imes180^circ}{n}-frac{360^circ}{n}=108^circ$$ => $$180n-360-360=108n$$ => $$180n-108n=720$$ => $$n=frac{720}{72}=10$$ => Ans - (A)
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