1. ∆PQR is right angled at Q. If sinP = 12/13, then what is the value of tanR ?
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By: anil on 05 May 2019 02.02 am
Given : $$sin P$$ = $$frac{12}{13}$$ Also, $$sin P=frac{QR}{PR}=frac{12}{13}$$ Let QR = 12 cm and PR = 13 cm Thus, in $$ riangle$$ PQR, => $$(PQ)^2=(PR)^2-(QR)^2$$ => $$(PQ)^2=(13)^2-(12)^2$$ => $$(PQ)^2=169-144=25$$ => $$PQ=sqrt{25}=5$$ cm To find : $$ an R=frac{PQ}{QR}$$ = $$frac{5}{12}$$ => Ans - (D)
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