1. The volume of metallic cylindrical pipe of uniform thickness is 748 c.c. Its length is 14 cm and its external radius is 9 cm. The thickness of the pipe is
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By: anil on 05 May 2019 01.50 am
Let internal radius = $$r$$ cm and external radius = $$R=9$$ cm Length of pipe = $$h=14$$ cm => Volume of pipe = $$pi(R^2-r^2)h=748$$ => $$frac{22}{7} imes 14 imes (9^2-r^2)=748$$ => $$44 imes (81-r^2)=748$$ => $$81-r^2=frac{748}{44}$$ => $$81-r^2=17$$ => $$r^2=81-17=64$$ => $$r=sqrt{64}=8$$ cm $$ herefore$$ Thickness of pipe = $$9-8=1$$ cm => Ans - (C)
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