1. 129 meter from the foot of a cliff on level of ground, the angle of elevation of the top of a cliff is 30°. The height of this cliff is
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By: anil on 05 May 2019 01.50 am
Given : BC = 129 m and $$angle$$ ACB = $$30^circ$$ To find : AB is the cliff = ? Solution : In $$ riangle$$ ABC, => $$tan(30^circ)=frac{AB}{BC}$$ => $$frac{1}{sqrt{3}}=frac{AB}{129}$$ => $$AB=frac{129}{sqrt{3}}$$
=> $$AB = 43sqrt3$$ m => Ans - (C)
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=> $$AB = 43sqrt3$$ m => Ans - (C)