1. In what ratio is the segment joining points (2, 3) and (-2, 1) divided by the Y-axis?
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By: anil on 05 May 2019 01.46 am
Using section formula, the coordinates of point that divides line joining A = $$(x_1 , y_1)$$ and B = $$(x_2 , y_2)$$ in the ratio a : b = $$(frac{a x_2 + b x_1}{a + b} , frac{a y_2 + b y_1}{a + b})$$ Let the ratio in which the segment joining (2,3) and (-2,1) divided by the y-axis = $$k$$ : $$1$$ Since, the line segment is divided by y-axis, thus x coordinate of the point will be zero, let the point of intersection = $$(0,y)$$ Now, point P (0,y) divides (2,3) and (-2,1) in ratio = k : 1 => $$0 = frac{(-2 imes k) + (2 imes 1)}{k + 1}$$ => $$-2k + 2 = 0$$ => $$k = frac{2}{2}=1$$ $$ herefore$$ Required ratio = 1 : 1 => Ans - (B)
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