67651. The transistor of following figure in Si diode with a base current of 40 μA and ICBO = 0, if VBB = 6V, RE = 2 kΩ and β = 90, IBQ = 20 μA then RB =
67652. In the amplifier circuit of figure hfe = 100 and hie = 1000 Ω. The voltage gain of amplifier is about
67653. The efficiency of a full wave rectifier using centre tapped transformer is twice that in full wave bridge rectifier.
67654. Assertion (A): CE amplifier is the most widely used BJT amplifierReason (R): CE amplifier has zero phase difference between input and output
67655. Assertion (A): For large signal variations an amplifier circuit has to be analysed graphicallyReason (R): The output characteristics of a transistor is nonlinear.
67656. Negative feedback reduces noise originating at the amplifier input.
67657. Maximum efficiency of class B power amplifier is 50%.
67658. In figure what is the base current if VBE = 0.7 V
67659. In figure ID = 4 mA. Then VS =
67660. The self bias provides
67661. In figure what is value of IC if βdc = 100. Neglect VBE
67662. In figure the saturation collector current is
67663. Consider the following statements : A clamper circuit adds or subtracts a dc voltage to a waveformdoes not change the waveformamplifiers the waveform Which are correct?
67664. In figure v1 = 8 V and v2 = 8 V. Which diode will conduct?
67665. A forward voltage of 9 V is applied to a diode in series with a 1 kΩ load resistor. The voltage across load resistor is zero. It indicates that
67666. Which power amplifier can deliver maximum load power?
67667. A CB amplifier has re = 6 Ω, RL = 600 Ω and a = 0.98. The voltage gain is
67668. A bridge rectifier circuit has input of 50 Hz frequency. The load resistance is RL and filter capacitance is C. For good output wave shape, the time constant RLC should be at least equal to
67669. Si transistor of following figure has a = 0.9 and ICE= 0, VEE = 5 V and VCC = 13 V, then RE will be if IEQ = 1 mA
67670. In class C operation of an amplifier circuit, the collector current exists for
67671. The 'h' parameters of the circuit shown in the figure are hib = 25 Ω, hfb = 0.999 and hob = 10-6Ω The Voltage gain is
67672. An exponential amplifier has diode in feedback path.
67673. DC amplifiers have a tendency to be unstable.
67674. A half wave diode rectifier has a capacitance input filter. If input voltage is Vm sin ωt, PIV is
67675. An amplifier with loop gain Aβ will be more stable for value of Aβ as
67676. Study the circuit of figure and examine the following statements It is an active low pass finer.It is a second order filter.The change in gain is 40 dB/decade. Which of the above statements are correct?
67677. In a circuit of figure, Vs = 10 cos(ωt) power drawn by the 2Ω resistor is 4 watts. The power factor is
67678. The quiescent collector current IC, and collector to emitter voltage VCE in a CE connection are the values when
67679. In the op-amp circuit of figure, V0 =
67680. Figure shows the self bias circuit for CE amplifier and its equivalent circuit. VBB and RB respectively are
67681. Figure is a 24 Vr stabilized power supply. The zener is 24 V, 600 mW. The minimum zener current is 10 mA. Proper values R and maximum load current are
67682. The open loop gain of an amplifier is 200. If negative feedback with β = 0.2 is used, the closed loop gain will be
67683. In a class C power amplifier the input signal has a frequency of 250 kHz. If the collector current pulses are 0.1 μs wide, the duty cycle of current waveform is
67684. In figure as the load resistance is changed
67685. In figure, voltage across R2 = + 10 V. If VBE = 0.7 V and VE = 0.7 V and RE = 10 kΩ, current through RE is
67686. A 12 kHz pulse wave-form is amplified by a circuit having an Upper cut-off frequency of 1 MHz. The minimum input pulse width that can be accurately reproduced is
67687. Feedback factor may be less or more than 1.
67688. An RC oscillator uses
67689. The main advantage of CMOS circuit is
67690. Ac signals are given to both inverting and non-inverting terminals of an op-amp. When will the output maximum
67691. An ideal op-amp has zero slew rate.
67692. In a bridge rectifier circuit the rms value of input ac voltage is 10 V. The PIV across each diode is
67693. In a half wave diode rectifier circuit the current flows in the load circuit for
67694. In a push pull circuit
67695. A transistor with a = 0.9 and ICBO = 10 μA is biased so that IBQ = 90 μA. Then IEQ will be
67696. In figure, transistor βdc = 100 and LED voltage when it is conducting is 2 V. Then the base current which saturates the transistor is
67697. In figure the dc emitter current of each transistor is about
67698. The input voltage for starting oscillations in an oscillator is caused by
67699. The current flowing in a certain P-N junction at room temperature is 2 x 10-7 Amp. When a large reverse biased voltage is applied. Calculate the current flowing when 0.1 volts is applied.
67700. In following figure find VDSQ by assuming gate current is negligible for the p-channel JFET. (if IDQ = - 6 mA, RS = 0, VDD = -18 V, RD = 2 kΩ, IDSS = - 10 mA, IPO = - 3 V)
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