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You Are On Multi Choice Question Bank SET 1354

67701. Which of the following power amplifiers has highest efficiency?





67702. A full wave rectifier using centre tapped transformer and a bridge rectifier use similar diodes and have equal no load output voltage. Under equal load conditions





67703. Assume that op-amp in figure is ideal. If input Vi is triangular, the output V0 will be





67704. In an amplifier with a gain of - 1000 and feedback factor β = - 0.1, the change in gain is 20% due to temperature. The change in gain for feedback amplifier will be





67705. A transistor has two p-n junctions. The batteries should be connected such that





67706. The value of parameter re used in re transistor model





67707. Assertion (A): In a full wave rectifier output the lowest ac component is at twice the input frequencyReason (R): In a full wave rectifier, the output waveform consists of half sinusoids





67708. An op-amp has zero gain for common mode inputs. Then CMRR =





67709. Assertion (A): Negative feedback reduces the bandwidth of an amplifier Reason (R): Negative feedback stabilizes the gain of an amplifier





67710. In an amplifier the voltage gain is the ratio of





67711. Find resistance RB to bring transistor to threshold of saturation VCB = 0, VBE = 0.7 V, a = 0.96





67712. In figure ID = 4 mA. Then VGS =





67713. A typical value of gm for a FET is about 25 μs.



67714. The dissipation at the collector is in the quiescent state and increases with excitation in the case of a





67715. In following circuit, RB will be if VCC = 10 V, VS = 2 V, RC = 5 kΩ, RS = 90 kΩ, β = 50, ICE = 0, VCEsat = 0.1 V





67716. The open loop gain of an ideal op-amp is





67717. In following figure, what will be R1 and R2 for maximum symmetrical swing if VCSat ≈ 0. Given that RE = 200 Ω, RC = 400 Ω, VCC = 20 V, β = 99





67718. The ideal characteristics of a stabilizer is





67719. The ripple factor of a half wave rectifier is more than 2.



67720. Assertion (A): The circuit in figure produces repetitive narrow pulses when input is fed with sine or triangular waveform having peak value more than + VReason (R): The high gain op-amp produces voltages at two levels. If input is more than + V, the output is + 15 V otherwise the output is - 15 V.





67721. In a CE amplifier drives a low load resistance directly the result will be





67722. For high frequencies a capacitor like





67723. A non-inverting op-amp summer is shown in figure, the output voltage V0 is




67724. In following figure find VGG by assuming gate current is negligible for the p-channel JFET. (if IDQ = - 6 mA, RS = 0, VDD = -18 V, RD = 2 kΩ, IDSS = - 10 mA, IPO = - 3 V)





67725. A difference amplifier using op-amp has closed loop gain = 50. If input is 2 V to each of inverting and non-inverting terminals, output is 5 mA. Then CMRR =





67726. The coupling capacitor in amplifier circuits





67727. In figure if C is replaced by short circuit then RB will be





67728. A full wave rectifier circuit using centre tapped transformer and a bridge rectifier are fed at 100 V, 50 Hz. The frequencies of outputs in these two rectifiers are





67729. When the ac base voltage in a CE amplifier circuit is too high, the ac emitter current is





67730. When load is coupled to class A amplifier through transformer, efficiency decreases.



67731. The gain of an FET amplifier can be changed by changing





67732. The open loop gain of an actual op-amp is about 100.



67733. In the circuit figure LED will be on when v1 is





67734. A differential amplifier consists of two CB amplifiers.



67735. Figure shows a portion of linear v - i characteristics of diode. If applied voltage is + 6 V, the current will be





67736. A power transistor dissipates 5 W. If ambient temperature is 30° and case to air thermal resistance is 10° C/W, the case temperature is





67737. An R-C coupled amplifier has mid-frequency gain of 200 and a frequency response from 100 Hz to 20 kHz. A negative feedback network with β = 0.2 is incorporated into the amplifier circuit, the Bandwidth will be





67738. In figure the zener current





67739. In a commercially available good power supply the voltage regulation is about





67740. In the circuit of figure the diode





67741. The most commonly used bias in BJT amplifier circuits is





67742. In the circuit of figure, v1 = v2 = 10 V. Then





67743. The inverting op-amp shown in the figure has an open loop gain to 100. The closed loop given is





67744. In a voltage regulated power supply the zener operates in the breakdown region when (Vin is input voltage and Vz is zener breakdown voltage)





67745. The parameter h11 for CB circuit is higher than that for CE circuit.



67746. Figure shows a self bias circuit for FET amplifier, ID = 4 mA. Then IS =





67747. In the CE equivalent circuit of figure, the voltage gain is





67748. In a CE amplifier





67749. The voltage gain of an amplifier without and with feedback are 100 and 20. The negative feedback is





67750. In the circuit shown in figure, RC = 10k, RE = 150Ω, β = 100, I = 1 mA. The value of , will be





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