1. Find the largest number that will divide 398,436 and 542 leaving remainder 7,11 and 15 respectively?





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MCQ-> Answer the questions based on the following information.A number arrangement machine, when given a particular input, rearranges it following a particular rule. Illustrations of the input and the steps of arrangement is given below. Input: 245, 316, 436, 519, 868, 710, 689 Step 1: 710, 316, 436, 519, 868, 245, 689 Step 2: 710, 316, 245, 519, 868, 436, 689 Step 3: 710, 316, 245, 436, 868, 519, 689 Step 4: 710, 316, 245, 436, 519, 868, 689 Step 4 is the last step for the given inputIf the input is given as “655, 436, 764, 799, 977, 572, 333”, which of the following step will be “333, 436, 572, 655, 977, 764, 799”?
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MCQ->Find the largest number that will divide 398,436 and 542 leaving remainder 7,11 and 15 respectively?....
MCQ-> In each of the following questions two rows of number are given. The resultant number in each row is to be worked out separately based on the following rules and the question below the row is to be answered. The operations of number progress from the left to right. Rules: (i) If an even number is followed by another even number they are to be added. (ii) If an even number is followed by a prime number, they are to be multiplied. (iii) If an odd number is followed by an even number, even number is to be subtracted from the odd number. (iv) If an odd number is followed by another odd number the first number is to be added to the square of the second number. (v) If an even number is followed by a composite odd number, the even number is to be divided by odd number.I. 84 21 13 II. 15 11 44 What is half of the sum of the resultants of the two rows ?....
MCQ-> Mathematicians are assigned a number called Erdos number (named after the famous mathematician, Paul Erdos). Only Paul Erdos himself has an Erdos number of zero. Any mathematician who has written a research paper with Erdos has an Erdos number of 1.For other mathematicians, the calculation of his/her Erdos number is illustrated below:Suppose that a mathematician X has co-authored papers with several other mathematicians. 'From among them, mathematician Y has the smallest Erdos number. Let the Erdos number of Y be y. Then X has an Erdos number of y+1. Hence any mathematician with no co-authorship chain connected to Erdos has an Erdos number of infinity. :In a seven day long mini-conference organized in memory of Paul Erdos, a close group of eight mathematicians, call them A, B, C, D, E, F, G and H, discussed some research problems. At the beginning of the conference, A was the only participant who had an infinite Erdos number. Nobody had an Erdos number less than that of F.On the third day of the conference F co-authored a paper jointly with A and C. This reduced the average Erdos number of the group of eight mathematicians to 3. The Erdos numbers of B, D, E, G and H remained unchanged with the writing of this paper. Further, no other co-authorship among any three members would have reduced the average Erdos number of the group of eight to as low as 3.• At the end of the third day, five members of this group had identical Erdos numbers while the other three had Erdos numbers distinct from each other.• On the fifth day, E co-authored a paper with F which reduced the group's average Erdos number by 0.5. The Erdos numbers of the remaining six were unchanged with the writing of this paper.• No other paper was written during the conference.The person having the largest Erdos number at the end of the conference must have had Erdos number (at that time):
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