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In question numbers 36 to 39, a series is given, with one term missing. Choose the correct alternative from the given ones that will complete the series.6 + $$\sqrt{216};7\ + \sqrt{343};8\ +\ \sqrt{512};9\ +\ \sqrt{729};$$ [u]?[/u]
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By: anil on 05 May 2019 04.05 pm
The pattern followed is = $$n+sqrt{n^3}$$ Eg :- 6 + $$sqrt{216};7 + sqrt{343};8 + sqrt{512};9 + sqrt{729};$$ Now, $$10^3=1000$$ Thus, the next term = $$10+sqrt{1000}$$ => Ans - (D)
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