1.
In each of the following questions, which of the following interchange of signs would make the given equation correct ?$$10+10\div10-10\times10=10$$
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eq10$$ (B) : $$10div10+10-10 imes10=10$$ = $$1+10-100=-89
eq10$$ (C) : $$10 imes10div10-10+10=10$$ = $$10-10+10=10$$ (D) : $$10div10+10-10 imes10=10$$ = $$1+10-100=-89
eq10$$
=> Ans - (C)