1. In the MBA Programme of a B - School, there are two sections A and B. 1/4th of the students in Section A and 4/9th of the students in section B are girls. If two students are chosen at random, one each from section A and Section B as class representative, the probability that exactly one of the students chosen is a girl, is :
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By: anil on 05 May 2019 02.39 am
Probability of choosing a boy from Section A = 3/4
Probability of choosing a boy from Section B = 5/9
Probability of choosing a girl from Section A = 1/4
Probability of choosing a girl from Section B = 4/9
There are two cases. Case 1: Boy from section A and girl from section B Probabilty = $$frac{3}{4}$$ x $$frac{4}{9}$$ Case 1: Boy from section A and girl from section B
Probabilty = $$frac{1}{4}$$ x $$frac{5}{9}$$
Adding gives final probability = $$frac{12}{36}$$ + $$frac{5}{36}$$ = $$frac{17}{36}$$
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Probability of choosing a boy from Section B = 5/9
Probability of choosing a girl from Section A = 1/4
Probability of choosing a girl from Section B = 4/9
There are two cases. Case 1: Boy from section A and girl from section B Probabilty = $$frac{3}{4}$$ x $$frac{4}{9}$$ Case 1: Boy from section A and girl from section B
Probabilty = $$frac{1}{4}$$ x $$frac{5}{9}$$
Adding gives final probability = $$frac{12}{36}$$ + $$frac{5}{36}$$ = $$frac{17}{36}$$